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Apr 16, 2014 · Use A = Ka. x = [H+] = [A-]. and b = [HA] you have A = x^2 / B ... multiply both sides by B. x^2 = AB then take sq root. x = sq root (AB) << the sq root is the last operation to be done ......
31. The roots of the quadratic equationax2+bx+c=0;a6= 0 are −b p b2 −4ac 2a The solution set of the equation is (−b+ p 2a; −b− p 2a) where = discriminant = b2 −4ac 32. The roots are real and distinct if >0. 33. The roots are real and coincident if = 0. 34. The roots are non-real if <0. 35. If and are the roots of the equation ax2 ...
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Oct 02, 2018 · KE = 1/2mv^2 (note KE is kinetic energy) You could rearrange for v as the subject 2KE = mv^2 v^2 = 2KE/m v = (2KE/m)^1/2 also you would not include plus or minus because a negative velocity makes no sense.
Define rearranging. rearranging synonyms, rearranging pronunciation, rearranging translation, English dictionary definition of rearranging. tr.v. re·ar·ranged , re·ar·rang·ing , re·ar·rang·es To change the arrangement of. re′ar·range′ment n.
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Dissociation equation of weak acid or base Calculate Ka from pl<a given Ka expression Assume 1. [ Assumptions for pH calculation — 10-PKa - 10 Conc of conjuc molL-l Starting concentration of weak acid or base Question: ml- of is titrated with up to a total of Of acid (or conj acid) pKa ( Acid In flask mol L -l mol L -l Base in burette
A useful equation can be derived by starting with the differential equation, setting kel = ka = k, using Laplace transforms. Using the Convolution Machine we get Equation 8.3.3. Equation 8.3.3 Laplace of Amount in the Body/Plasma (Xp) where kel = ka = k